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Full tensors solutions

To: cmtcustomers@ldeo.columbia.edu
Subject: quick CMT: 2012/12/06, 21:33:28.0, BOUVET ISLAND REGION, MW=5.4
X-Scanned-By: MIMEDefang 2.49 on 129.236.10.30


Here is the solution for the recent event.

December 6, 2012, BOUVET ISLAND REGION, MW=5.4

Howard Koss

CENTROID-MOMENT-TENSOR  SOLUTION
GCMT EVENT:     C201212062133A  
DATA: IU CU MN II IC G  GE LD DK
L.P.BODY WAVES: 93S, 138C, T= 40
SURFACE WAVES: 133S, 238C, T= 50
TIMESTAMP:      Q-20121207072144
CENTROID LOCATION:
ORIGIN TIME:      21:33:29.8 0.1
LAT:54.25S 0.01;LON:  1.39W 0.01
DEP: 12.0  FIX;TRIANG HDUR:  1.2
MOMENT TENSOR: SCALE 10**24 D-CM
RR=-0.149 0.017; TT= 1.050 0.017
PP=-0.896 0.018; RT=-0.361 0.043
RP= 0.272 0.044; TP=-0.931 0.015
PRINCIPAL AXES:
1.(T) VAL=  1.537;PLG=15;AZM=202
2.(N)      -0.249;    74;    358
3.(P)      -1.283;     6;    111
BEST DBLE.COUPLE:M0= 1.41*10**24
NP1: STRIKE=246;DIP=75;SLIP= 174
NP2: STRIKE=337;DIP=84;SLIP=  15

            ###########           
        ----###############       
      -------################     
    ----------#################   
   ------------#################  
  --------------############----- 
  ---------------####------------ 
 ---------------##----------------
 ------------#####----------------
 --------##########---------------
 ------#############--------------
  --#################----------   
  -##################---------- P 
   ###################---------   
    ##################---------   
      #####   #########------     
        ### T ##########---       
              #########           


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To: alert@emsc-csem.org, m.d.zirbes@gmail.com, zirbes@usgs.gov
Subject: USGS Body-Wave Moment Tensor Solution

12/12/06 21:33:26.30

Epicenter: -54.216   -1.983
MW 5.3

USGS MOMENT TENSOR SOLUTION
Depth   4         No. of sta: 18
Moment Tensor;   Scale 10**17 Nm
  Mrr= 0.25       Mtt= 0.47
  Mpp=-0.72       Mrt= 0.58
  Mrp=-0.19       Mtp=-0.65
 Principal axes:
  T  Val=  1.16  Plg=34  Azm= 23
  N       -0.15      56      209
  P       -1.01       3      115

Best Double Couple:Mo=1.1*10**17
 NP1:Strike=164 Dip=65 Slip=  23
 NP2:        64     69       153


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